Cron output & logging

A basic solution:
use $() for executing date command and return output
format datetime to UTC, escape the % character with \
add 2>&1 at the end for streaming both stdout and stderr into that log file
Example:
* * * * * echo "Test crontab log" > /tmp/crontab.log.$(date --utc +\%Y\%m\%d_\%H\%M\%SZ) 2>&1
Output:
ls -lh /tmp | grep log
​
-rw-rw-r-- 1 ubuntu  ubuntu    17 May  4 05:06 crontab.log.20190504_050601Z
-rw-rw-r-- 1 ubuntu  ubuntu    17 May  4 05:07 crontab.log.20190504_050701Z
Reference
1.​https://unix.stackexchange.com/questions/29578/how-can-i-execute-date-inside-of-a-cron-tab-job/517052#517052​
2.​https://crontab.guru/​
3.​https://yasoob.me/posts/6-tips-before-you-write-your-next-bash-cronjob/​

Colorize logs

Signal

Last modified 3yr ago